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4 votes
Solve for the variable in the following equation: 1 / 6c + 1 / 3 = - 2

A. c = −30

B. c = 26

C. c = −14

D. c = 12

User Phyliss
by
6.9k points

2 Answers

4 votes

Answer:

C. c = −14

Explanation:

Combine multiplied terms into a single fraction


(1)/(6) c+(1)/(3) = - 2


(1c)/(6) +(1)/(3) =-2

Multiply by 1


(1c)/(6) +(1)/(3) =-2


(c)/(6) +(1)/(3) =-2

Subtract
(1)/(3) from both sides of the equation


(c)/(6) +(1)/(3) =-2


(c)/(6) +(1)/(3) -(1)/(3) =-2-(1)/(3)

Subtract the numbers


(c)/(6) +(1)/(3) -(1)/(3) =-2-(1)/(3)


(c)/(6) =-2-(1)/(3)

Subtract the numbers


(c)/(6) =-2-(1)/(3)


(c)/(6) =-(7)/(3)

Multiply all terms by the same value to eliminate fraction denominators


(c)/(6) =-(7)/(3)


c (c)/(6) =6(-(7)/(3) )

Cancel multiplied terms that are in the denominator


c (c)/(6) =6(-(7)/(3) )

c = 6
(-(7)/(3) )

Multiply the numbers

c = 6
(-(7)/(3) )

c = - 14

User Ankur Dhanuka
by
6.0k points
4 votes

Answer: C. C=-14

Explanation:

Given

(1/6)c+1/3=-2

Multiply both sides by the LCM of 1/6 and 1/3(Least Common Multiple)

6[(1/6)c+1/3]=(-2)(6)

c+2=-12

Subtract 2 on both sides

c+2-2=-12-2

c=-14

Hope this helps!! :)

Please let me know if you have any questions

User Chateau
by
6.8k points
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