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RS= 4y+2, ST = 3y+8, and RT = 38 what is the value of y
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RS= 4y+2, ST = 3y+8, and RT = 38 what is the value of y

User Savi
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1 Answer

4 votes

Answer:

y = 4

Explanation:

Given that,

RS= 4y+2, ST = 3y+8, and RT = 38

We need to find the value of y.

As,

RT = RS+ST

Put all the values,

38 = 4y+2+3y+8

38-2-8 = 4y+3y

28 = 7y

y = 4

So, the value of y is equal to 4.

User CyclingDave
by
5.4k points
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