Question

Can yall help me with this one, thanks!

Answer 1

Element atom molar mass Total % composition

Na 1 23 40 57.5 %

O 1 16 40 40%

H 1 1 40 2.5 %

The given compound is NaOH.

Na : number of atom= 1

Molar mass= 23 g/mol

Total mass of NaOH = 40 g/mol

% composition by mass =
`\frac{\text {mass of atom}}{\text {Total mass}}* 100=(23)/(40)* 100=57.5\%`

O : number of atom= 1

Molar mass= 16 g/mol

Total mass of NaOH = 40 g/mol

% composition by mass =
`\frac{\text {mass of atom}}{\text {Total mass}}* 100=(16)/(40)* 100=40\%`

H : number of atom= 1

Molar mass= 1 g/mol

Total mass of NaOH = 40 g/mol

% composition by mass =
`\frac{\text {mass of atom}}{\text {Total mass}}* 100=(1)/(40)* 100=2.5\%`