Question

Find AC and BC.

Answers:
14.94
13.46
11.10
10
Please help.

Answer 1

Explanation:

Use Sine rule.

`(ac)/( \sin(b) ) = (ab)/( \sin(c) ) \\ (ac)/( \sin(90) ) = (10)/( \sin(42) ) \\ ac \sin(42) = 10 \sin(90) \\ ac = (10 \sin(90) )/( \sin(42) ) \\ ac = 14.9 \: units \: (3s.f)`

Angle A + angle B + angle C = 180 (sum of angles in triangle)

Angle A + 90 + 42 = 180

Angle A + 132 = 180

Angle A = 180 - 132

= 48

`(bc)/( \sin(a) ) = (ab)/( \sin(c) ) \\ (bc)/( \sin(48) ) = (10)/( \sin(42) ) \\ bc \sin(42) = 10 \sin(48) \\ bc = (10 \sin(48) )/( \sin(42) ) \\ = 11.1units (3sf)`