129k views
0 votes
You have one type of nut that sells for $4.50/lb and another type of nut that sells for $8.00/lb. You would like to have 28 lbs of a nut mixture that sells for $7.80/lb. How much of each nut will you need to obtain the desired mixture?

You will need
lbs of the cheaper nut
and
lbs of the expensive nut.

User Yoonjung
by
2.8k points

1 Answer

2 votes

Answer:

I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.

Explanation:

Since I have one type of nut that sells for $ 4.50 / lb and another type of nut that sells for $ 8.00 / lb, and I would like to have 28 lbs of a nut mixture that sells for $ 7.80 / lb, to determine how much of each nut will I need to obtain the desired mixture, the following calculation must be performed:

8 x 0.95 + 4.5 x 0.05 = 7.825

8 x 0.94 + 4.5 x 0.06 = 7.79

0.94 x 28 = 26.32

26.4 x 8 + 1.6 x 4.5 = 218.4

218.4 / 28 = 7.8

Thus, I will need 26.4 pounds of the expensive nuts and 1.6 pounds of the cheap nuts.

User Pruthvi Kumar
by
3.2k points