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CaCN2 + 3H20 - CaCO3 + 2NH3

What is the percent yield if 15.5 g of NH3
is produced upon reaction of 65.5 g of CaCN2
and 451 g of water? The molar mass of CaCN2
is 80.11 g/mol and the molar mass of CaCO3
is 100.09 g/mol.
1. 1.79 %
2. 14.5 %
3. 69.7 %
4. 89.75 %
5. 27.8 %
6. 55.8 %
7. 80.15 %

User Qkhhly
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1 Answer

5 votes

Answer:3

Step-by-step explanation:

User Joe Sleiman
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