1 Answer

Abhik Chakraborty · Answer 1 · 2022-02-22T06:10:26+0000

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of
$(h\circ g)(-6)$ .

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting
b=-6 , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

$(h\circ g)(-6)=[-39-10]^2$

$(h\circ g)(-6)=[-49]^2$

$(h\circ g)(-6)=2401$

Therefore, the value of
$(h\circ g)(-6)$ is 2401.

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