Question

1. How many grams are in 1.7 x 10^23 particles of Cl2?

2. How many moles are in 3.28 x 10^23 atoms of NaCl? *

3. If I were to determine how many liters 26 grams of water is, what type of conversion would this be? *

A Mass --> Moles --> Particles
B Mass --> Moles --> Volume
C Volume --> Mass --> Moles
D Moles --> Mass --> Volume

Answer 1

Answer: 1. 20.0 grams

2. 0.272 moles

3. B) Mass --> Moles --> Volume

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadros number}}` or

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` or

Putting in the values we get:

1.
`\text{Number of moles of} Cl_2=(1.7* 10^(23))/(6.023* 10^(23))=0.282moles`

Mass of
`Cl_2=moles* {\text {Molar mass}}=0.282mol* 71g/mol=20.0g`

2.
`\text{Number of moles of NaCl}=(3.28* 10^(23))/(2* 6.023* 10^(23))=0.272moles`

3.
`\text{Number of moles of water}=(26g)/(18g/mol)=1.44moles`

Volume of water =
`moles* {\text {Molar volume}}=1.44mol* 22.4L/mol=32.4L`