Question

An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its

final volume is 1.75 L. What was the initial temperature?

Answer 1

`T_1=-91.18\°C`

Step-by-step explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

`(T_1)/(V_1)= (T_2)/(V_2)`

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

`T_1= (T_2V_1)/(V_2)\\\\T_1= ((18.00+273.15)K(1.75L))/((2.80L))\\\\T_1=182K-273.15\\\\T_1=-91.18\°C`

Best regards!