Question

What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters

Answer 1

Question:

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

Answer:

The new pressure is: 1.896 atm

Step-by-step explanation:

At standard temperature and pressure, we have:

`P_1 = 1atm`

`T_1 = 273.15k`

`V_1 = 3.5L`

Outside, we have:

`T_2 = 296k`

`V_2 = 2.0L`

Required

Determine the new pressure

Using combined gas law, we have:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

This gives:

`(1 * 3.5)/(273.15) =(P_2*2.0)/(296)`

Solve for
`P_2`

`P_2 = (296 * 1 * 3.5)/(273.15*2.0)`

`P_2 = (1036)/(546.30)`

`P_2 \approx 1.896 atm`