Answer:
We want to prove that the sine of an angle equals the cosine of its complement.
\sin(\theta) = \cos(90^\circ-\theta)sin(θ)=cos(90
∘
−θ)sine, left parenthesis, theta, right parenthesis, equals, cosine, left parenthesis, 90, degrees, minus, theta, right parenthesis
[I'm skeptical. Please show me an example.]
Let's start with a right triangle. Notice how the acute angles are complementary, sum to 90^\circ
∘
degrees.
Step-by-step explanation: cosine F equals 40 over 9 comma cosine E equals 9 over 40