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1) A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force? 2) The same spring is stretched 5 m. What was the force?​

1) A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force-example-1
User Jedd
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1 Answer

9 votes

Answer:

  1. K= F/∆l
  2. F=K•∆l
  3. ∆l=F/K
  4. so we know that the K is 0.70N/m
  5. the ∆l which is the elongation is 1.5 m
  6. to find the force which is F u have to apply the formula.
  7. by applying the formula you get 1.05N
  8. for the second force you get 3.5N
User Alanpatchi
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