Question

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An ideal gas triples in volume in an adiabatic process. the initial pressure is 1.4 x 10^5 Pa. what is the final pressure? let y = 1.67.
5.8 x 10^4 Pa
2.2 x 10^4 Pa
1.4 x 10^4 Pa
1.0 x 10^5 Pa​

Answer 1

Answer: 2.2x10^4

Explanation: in a adiabatic process pV^y = constant.

So V2=3V1 and p2 = p1 / 3^1.67 = 2.2x10^4 Pa