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4 votes
Find a value of k such that kx2 + 12x − 4 = 0 has one real-number solution. Explain.

2 Answers

1 vote
The answer is 0.6!

Explanation
User Panpawel
by
5.0k points
3 votes

Answer: if x is to the 2 power then

kx^2+12x-4=0 Add 4 to the both sides

kx^2+12x=4 Divide both sides by 12

kx^2=1/3x square root the both sides

k=0.6x

Explanation:

User Bert H
by
5.6k points
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