Question

What's the distance between (4,-2) and (4,3)

Answer 1

5 units

Explanation:

(4, -2 ) ;
`x_(1)=4` and
`y_(1) = -2`

(4 , 3) ;
`x_(2) = 4` and
`y_(2)=3`

distance =
`\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}\\`

`= \sqrt{(4-4)^(2)+(3-[-2])^(2)}\\\\= \sqrt{0+(3+2)^(2)} \\\\=\sqrt{5^(2)}\\\\= 5 units`