Question

PLEASE Answer asap!!!!

Answer 1

x=0

Explanation:

The axis of symmetry:
`x=(-b)/(2a)` when the equation is
`y=ax^2+bx+c`

The given equation is:

`y=x^2-6`

To make the a and b values more easily identifiable, we can rewrite it like this:

`y=1x^2+0-6`

Now, we can tell that a=1 and b=0. Plug these into the equation
`x=(-b)/(2a)` :

`x=(-(0))/(2(1))\\x=0`

Therefore, the equation for the axis of symmetry for the parabola is x=0.

I hope this helps!