Question

Let f(x)=x^2+2 and g(x)=1-3x Find each function value. f(g(-1))

Answer 1

12

Explanation:

(x^2+2)*(1-3x)=-3x^3+x^2-6x+2

now plug in -1

-3(-1)^3+(-1)^2-6(-1)+2=12

hope this helped

Answer 2

78

Explanation: