Question

A heater has a resistance of 15 Ω. It operates on 120 V. What thermal energy is supplied by the heater in 2 minutes?

Answer 1

E = 115.2 kJ

Step-by-step explanation:

Given that,

Resistance, R = 15 ohms

Voltage, V = 120 V

We need to find the energy supplies by the heater in 2 minutes or 120 s.

The formula for the thermal energy supplies is given by :

`E=I^2Rt`

We know that, V = IR

So,

`E=(V^2t)/(R)\\\\E=((120)^2* 120)/(15)\\\\E=115200\ J\\\\E=115.2\ kJ`

So, 115.2 kJ of energy is supplied.