Question

How many grams of KCl are made when 5.02 moles of

ZnCl2 react in the reaction below?
2KMnO4 + ZnCl2 → 2KCl + Zn(MnO4)2
lol pls help me

Answer 1

Answer: 747.98 grams of KCl are made when 5.02 moles of
`ZnCl_2` react in the reaction.

Step-by-step explanation:

The balanced chemical equation is:

`2KMnO_4+ZnCl_2\rightarrow 2KCl+Zn(MnO_4)_2`

According to stoichiometry:

1 mole of
`ZnCl_2` produce = 2 moles of
`KCl`

Thus 5.02 moles
`ZnCl_2` will produce =
`(2)/(1)* 5.02=10.04` moles of
`KCl`

Mass of
`KCl=moles* {\text {molar mass}}=10.04mol* 74.5g/mol=747.98g`

Thus 747.98 grams of KCl are made when 5.02 moles of
`ZnCl_2` react in the reaction.