Question

What is output?

public class Division{
public static double division(double a, double b) throws Exception {
if(b == 0)
throw new Exception("Invalid number.");
return a / b;
}
public static void main(String[] args) {
try {
System.out.println("Result: " + division(5, 0));
}
catch (ArithmeticException e) {
System.out.println("Arithmetic Exception Error");
}
catch (Exception except) {
System.out.println("Division by Zero");
}
catch(Throwable thrwObj) {
System.out.println("Error");
}
}
}
A. Error.
B. Arithmetic Exception Error.
C. Arithmetic Exception Error Division by Zero Error.
D. Division by zero.

Answer 1

D. Division by zero.

Step-by-step explanation:

This Java code that is being provided in the question will output the following error.

Division by zero

This is because the main method is calling the division method and passing 0 for the variable b. The method detects this with the if statement and creates a new Exception. This exception is grabbed by the catch(Exception exception) line and prints out the error Division by zero.