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A 1.50-kg cart rolls along a horizontal table at a constant speed of 1.70 m/s. A ball of soft putty is dropped from a stationary hand onto the cart as it passes underneath. If the speed of the cart is reduced to 1.53 m/s, calculate the mass of the ball of putty. This collision is completely inelastic

User Ptikobj
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2 Answers

5 votes

Final answer:

The mass of the ball of putty that, when dropped onto a moving cart, caused its speed to reduce from 1.70 m/s to 1.53 m/s is calculated to be 0.167 kg (or 167 grams) by applying the conservation of momentum formula for an inelastic collision.

Step-by-step explanation:

To calculate the mass of the ball of putty dropped onto a cart causing a reduction in speed, we can apply the conservation of momentum, which states that the total momentum before a collision is equal to the total momentum after the collision, assuming no external forces act on the system.

The formula for conservation of momentum in a completely inelastic collision, where the two objects stick together after the collision, is given by:

m1 × v1 before + m2 × v2 before = (m1 + m2) × v after

We know the following:


  • Mass of cart, m1 = 1.50 kg

  • Initial speed of the cart, v1 before = 1.70 m/s

  • Final speed of the cart and putty, v after = 1.53 m/s

  • Initial speed of the putty, v2 before = 0 m/s (as it is dropped from a stationary hand)

Substitute these values into the momentum conservation formula:

1.50 kg × 1.70 m/s + m2 × 0 m/s = (1.50 kg + m2) × 1.53 m/s

Simplify and solve for m2 (mass of the putty):

m2 = ((1.50 kg × 1.70 m/s) - (1.50 kg × 1.53 m/s)) / (1.53 m/s)

Calculate the mass of the putty:

m2 = (2.55 kg·m/s - 2.295 kg·m/s) / 1.53 m/s

m2 = 0.167 kg or 167 grams

User Mattsap
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7.3k points
3 votes

Answer:

0.17 kg

Step-by-step explanation:

mc = mass of cart

mb = mass of ball

vc = speed of cart before collision

vb = speed of ball before collision (vb = 0)

v' = speed of cart and ball after collision

mc . vc + mb . vb = (mc + mb) . v'

(1.5)(1.7) + mb(0) = (1.5 + mb) . 1.53

2.55 + 0 = (1.5 + mb) . 1.53

2.55/1.53 = 1.5 + mb

5/3 = 3/2 + mb ( I change it to fraction)

mb = 5/3 - 3/2 = 10/6 - 9/6 = 1/6 kg

mb = 1/6 kg = 0.17 kg

User Jisson
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