Answer:
Tom Brady
30.2832 m^2 or 26(pi) m^2
Explanation:
There are three different shapes (right triangle, rectangle, and half-circle). To find the area of the whole you find the area of all of these things then add them.
Triangle: (axb/2)
- The first thing we must do is determine the lengths of the triangle.
- a: Because the diameter of the circle directly across from the triangle we can use this as side a
- b: To find be we take 10-2 because the 2 is what is used for the rectangle making the 8 what is left over for our side b
- (axb)/2 = (4x8)/2 = 32/2 = 16 m^2
Rectangle: (lxw)
- The first thing we will do is confirm the length and width of the rectangle
- l: The diameter is the length of the rectangle l=4
- w: Because the top portion of the area meets at the point where the triangle and rectangle converge the width is 2
- lxw = 4x2 = 8 m^2
Half-Circle: {(pi/2)(r)^2
- r: The only variable we need is the radius which is just half of the diameter. Therefore r=2
- {(pi/2)(r)^2} = {(pi/2)(2)^2} = {(pi/2)(4)} = 2(pi) = 6.2832
The Area of the Whole:
- Triangle: 16 m^2
- Rectangle: 8 m^2
- Half-Circle: 2(pi) or 6.2832 m^2
- 16+8+2(pi) = 26(pi) m^2 OR 16+8+6.2832 = 30.2832 m^2