Question

Solve each system using the elimination method
4x-y=-2
2x+y=2

Answer 1

`\left \{ {{x=0} \atop {y=2}} \right.`

Step-by-step explanation:
`\left \{ {{4x-y=-2} \atop {2x+y=2}} \right.`

Add the two equations

`4x-y+(2x+y)=-2+2`

Remove parentheses

`4x-y+2x+y=-2+2`

Cancel one variable

`4x+2x=-2+2`

Apply the Inverse Property of Addition

`4x+2x=0`

Combine like terms

`6x=0`

Divide both sides by the equation by the coefficient of variable

`x=0`

Substitute into one of the equations

`2*0+y=2`

Apply Zero Property of Multiplication

`y=2`

The solution of the system is

`\left \{ {{x=0} \atop {y=2}} \right.`

I hope this helps you

:)