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In the following quadratic equations find y-intercept and axis of symmetry 0 = 2x^2 - x + 3
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In the following quadratic equations find y-intercept and axis of symmetry

0 = 2x^2 - x + 3

User Hatem Alimam
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1 Answer

7 votes
Axis of symmetry:
-b/2a= -(-1)/2(2)= 1/4
Y-intercept:
(0,3)
User Erik Gillespie
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