Question

2) A 0.4 kg ball moves in horizontal circle of radius 3 mat speed of 100m/s. What

is the centripetal force?
file the​

Answer 1

9514 1404 393

Answer:

1333.3 N

Explanation:

The centripetal acceleration is given by ...

a = v^2/r

a = (100m/s)^2/(3 m) = (10^4)/3 m/s^2

Then the force on the ball is ...

F = Ma = (0.4 kg)(10^4)/3 kg·m/s^2 ≈ 1333.3 N