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Line l is perpendicular to the graph of the equation 2x-5y=10 and contains the point (-4,—3)

User Orberkov
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2 Answers

6 votes
6 votes
Answer : Line I is y= -5/2x - 13
It is written down and boxed in the attachment below .
Line l is perpendicular to the graph of the equation 2x-5y=10 and contains the point-example-1
User Shrikant K
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2.7k points
14 votes
14 votes

Answer:

5x +2y = -26

Explanation:

When you are given the equation of a line in standard form, you can immediately write most of the equation for the perpendicular line. It uses the same coefficients, but swapped, with one of them negated. The constant will be chosen to make the line pass through the given point.

Perpendicular line:

5x +2y = constant

5x +2y = 5(-4) +2(-3) = -20 -6

5x +2y = -26 . . . . . perpendicular line through (-4, -3)

Line l is perpendicular to the graph of the equation 2x-5y=10 and contains the point-example-1
User Paulus Potter
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3.2k points