Given :
- The length of a rectangle is thrice it's breadth.
- The perimeter of the rectangle is 88.
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To Find :
The Length and breadth of the rectangle.
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Solution :
We know that,

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Let's assume the breadth of the rectangle as x cm. Then the length will become 3x.
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Now, Substituting the given values in the formula :



Dividing 8 by both sides :


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Therefore,

