Question

What are the solution(s) to the quadratic equation 40 – x2 = 0? 0x = +2/10 x = +4/10 O x = +2/5 O x = 1415​

Answer 1

We are given with a quadratic equation and have to find its solution(s) :

`{:\implies \quad \sf 40-x^(2)=0}`

Transpose x² to RHS ;

`{:\implies \quad \sf x^(2)=40}`

`{:\implies \quad \sf x=\pm \: √(40)}`

`{:\implies \quad \sf x=\pm \: √(2* 2* 2* 5)}`

`{:\implies \quad \sf x=\pm \sqrt{\underline{\underline{2* 2}}* 2* 5}}`

`{:\implies \quad \bf \therefore \quad \underline{\underline{x=\pm 2√(10)}}}`

Answer 2

Hey there!

40 - x^2 = 0

-x^2 + 40 = 0

SUBTRACT 40 to BOTH SIDES

-x^2 + 40 - 40 = 0 - 40

SIMPLIFY IT!
-x^2 = -40

DIVIDE -1 to BOTH SIDES

-x^2/-1 = -40/-1

SIMPLIFY IT!
x = ± 2√10

Therefore, your answer is:

x = 2√10 or x = x = -2√10

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)