Question

Fig_Q5

6. A steel rod is stressed by a tension force of 250 N. It is found that the rod has length of 45
m and diameter of 1.5 mm. If the modulus of elasticity of the steel rod is assumed as 2 x 105
MPa, determine the strain of the steel rod due to the applied force.

Answer 1

The strain of the steel rod due to the applied force is 41.93

Step-by-step explanation:

Modulus of elasticity is equal to stress divided by strain.

And stress is equal to force divided by area

Surface area of cylindrical rod

`2\pi r (r+h)`

Substituting the given values we get -

`2 *3.14 * (1.5)/(1000) * 45 (45 + (1.5)/(1000)) = 19.07`

`2 * 10 ^5 = (250)/(19.07 * S=((\Delta L)/(L) ))`

Hence, strain is equal to

Strain = 41.93