Question

He measured the pool’s dimensions to be 15 feet long by 35 feet wide. The actual dimensions of the pool are 14.5 feet by 34.75 feet. Find Jack’s percent error to the nearest percent.

Answer 1

Percent error = -4.02 (Approx.)

Explanation:

Given:

Estimated pool dimension = 15 ft long and 35 ft wide

Actual pool dimension = 14.5 ft long and 34.75 ft wide

Find:

Percent error

Computation:

Area of Estimated pool = 15 x 35

Area of Estimated pool = 525 ft²

Area of Actual pool = 14.5 x 34.75

Area of Actual pool = 508.875 ft²

Percent error = [(Actual - Estimated) / Estimated]100

Percent error = [(508.875 - 525) / 525]100

Percent error = [(-21.125) / 525]100

Percent error = -4.02 (Approx.)