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What is the surface area of the cylinder with height 5 mi and radius 6 mi? Round your answer to the nearest thousandth.

User Hamed Aj
by
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2 Answers

4 votes

Answer: 414.69 m2

Explanation:

User Naim Rajiv
by
8.3k points
4 votes

Explanation:

Given

h = 5 mi

r = 6 mi

Surface Area of Cylinder =


2\pi \: rh + 2\pi {r}^(2) \\ = 2\pi(6)(5) + 2\pi ({6}^(2)) \\ = 2\pi(30) + 2\pi(36) \\ = 60\pi + 72\pi \\ = 132\pi \\ = 414.690 {mi}^(2) (nearest \: thousandth)

User Variag
by
7.8k points

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