Question

A container at equilibrium contains the following concentrations: [Hz] - 0.30 M and [HI]

0.90 M. The equilibrium constant is equal to 6.0. What is the concentration of I2 at
equilibrium?
Hzig) + 1218 = 2 Hle)

Answer 1

Answer: The concentration of
`I_2` at equilibrium is 0.45 M

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_c`

For the given chemical reaction:

`H_2(g)+I_2(g)\rightarrow 2HI(g)`

The expression for
`K_c` is written as:

`K_c=([HI]^2)/([H_2]^1[I_2]^1)`

`6.0=((0.90)^2)/((0.30)^1* (I_2)^1)`

`[I_2]=0.45M`

Thus concentration of
`I_2` at equilibrium is 0.45 M