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Question: The graph of a second-order polynomial is shown below, and the intercepts with the axes are marked. Explain how you can use the graph to write the polynomial as a product of linear factors (x-a)(x-b). Be sure to state the values of a and b. NEED HELP ASAP​

Question: The graph of a second-order polynomial is shown below, and the intercepts-example-1

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Hello!

Here we are given a second-order polynomial, and the root form of the function.


y=a(x-c)(x-d)

Where c and d are zeros of the function, which is where the graph intersects the x-axis.


y=a(x+4)(x-3)


-6=a(2+4)(2-3)


-6=-6a


a=1

Therefore, the equation of this polynomial would be
y=(x+4)(x-3), and the values of a and b would be the x-intercepts.

Hope this helps!

User Tzach Ovadia
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