Question

Find the eighth term of a geometric sequence for which a,3 = 35 and r= 7.​

Answer 1

588245.

Step-by-step explanation:

nth term = an = a1 r^(n-1) where a1 = the first term

a3 = 35 = a1 7^(3 - 1)

35 = a1* 49

a1 = 35/49 = 5/7

So the 8th term = (5/7)* (7)^7

= 588245