Question

Mr. Bennett wants to evaluate the cost of a warehouse. He

estimated the warehouse to be 400 feet long and 150 feet
wide. The actual dimensions of the warehouse are 320 feet
long and 100 feet wide. What was the percent error in
Mr. Bennett's calculation of the area of the warehouse?
Round to the nearest hundredth.
I NEED HELP

Answer 1

-46.677%

Explanation:

The computation of the percent error is shown below:

As we know that

Area of the warehouse = length × width

Based on estimated values, the area is

= 400 × 150

= 60,000

And, based on actual values, the area is

= 320 × 100

= 32,000

Now the percent error is

= (32,000 - 60,000) ÷ 60,000 × 100

= -46.677%