Question

What is the Ka of a 0.0981 M

solution of hydrocyanic acid
(HCN) with a pH of 6.00?
Ka = [?] x 10!?)

Answer 1

The answer is 1.02x10^-11

Step-by-step explanation:

Fill in the box 1.02 and then -11

Answer 2

Attached picture

Ka = [?] x 10

1.02 x 10^-11 = [?] x 10

[?] = 1.02 (I'm assuming you're asking this)

(If not then divide the 10)