Question

What is the value of the equilibrium constant K ?

Answer 1

K = 0.0209

Step-by-step explanation:

K =
`([H_(2)][I_(2)])/([2HI]^(2))`

K =
`([4.35 x 10^(-2) ][2.79 x 10^(-2) ])/([0.241]^(2) )`

K = 0.0208958

K = 0.0209