Question

A carnival ride starts at rest and is accelerated from an initial angle of zero to a final angle of 6.3 rad by a rad counterclockwise angular acceleration of 2.0 s2 What is the angular velocity at 6.3 rad?​

Answer 1

The angular velocity of the carnival ride at 6.3 rad with an angular acceleration of 2.0 rad/s² is found to be 5.0 rad/s using the kinematic equations for rotational motion.

Step-by-step explanation:

The question relates to a scenario where a carnival ride experiences angular acceleration and we want to find its angular velocity at a certain angle. To solve this physics problem, we can use one of the kinematic equations adapted for rotational motion, specifically the equation ω² = ω₀² + 2αθ, where ω is the final angular velocity, ω₀ is the initial angular velocity (in this case 0 rad/s because it starts from rest), α is the angular acceleration, and θ is the angle in radians through which the ride has rotated.

Plugging in the values:

• α = 2.0 rad/s²
• θ = 6.3 rad

We calculate:

ω² = 0 + 2(2.0 rad/s²)(6.3 rad) = 25.2 rad²/s²

So, ω = √(25.2 rad²/s²) = 5.0 rad/s

Therefore, the angular velocity at 6.3 rad is 5.0 rad/s.

Answer 2

Answer: 5.0 rad/s

Explanation: Because that’s what khan said so try it out.