Question

Write the equation of the line that goes through the point (3, 7) and has a slope of 2 in point-slope form.

Remember that point-slope form is `y\ -\ y_{1}\ =\ m\left(x\ -\ x_{1}\right)`



Once you have your equation, graph its line on the coordinate plane to the left.

Answer 1

Point-slope form
y-7=2(x-3)
Slope intercept
y-7=2(x-3)
y-7=2x-6
y=2x-6+7
y=2x+1

Where y-intercept is 1 ,slope is 2. Start from y 1 on the graph count 2 rise and 1 run.

Answer 2

Explanation:

All we need to do here is to employ the point-slope formula for the equation of a straight line: y - k = m(x - h). Here h = 3, k = 7 and m = 2. After substituting these values into y - k = m(x - h), we get:

y - 7 = 2(x - 3) (point-slope form)

This is perfectly adequate/correct, but it can be simplified into slope-intercept form y = mx + b:

y = 2x - 14 + 21, or

y = 2x + 7 Clearly, the y-intercept is 7 and the slope is 2. This is the slope-intercept form.

To graph this line, let x = 0. Then the y-intercept is (0, 2). Plot this. Next, find the x-intercept: Let y = 0 and solve the resulting equation for x:

0 = 2x + 7, or 2x = -7, or x = -7/2. Plot this (-7/2, 0). Finally, draw a line through these two points (0, 2) and (-7/2, 0).