Question

On a standardized exam, the scores are normally distributed with a mean of 120 and

a standard deviation of 10. Find the z-score of a person who scored 115 on the exam

Answer 1

Answer: z=−1.1

Explanation:

z=\frac{x-\mu}{\sigma}

z=

σ

x−μ

​

z-score formula

z=\frac{104-115}{10}

z=

10

104−115

​

Plug in values

z=\frac{-11}{10}

z=

10

−11

​

Subtract

z=-1.1

z=−1.1

Divide

Answer 2

Answer: z= -0.5

Step-by-step explanation: mean m=120 and deviation s=10.

Z = (x-m)/s= (115-120)/10