Step-by-step explanation:
Step-by-step explanation:
If an object having initial velocity
uExplanation:
If an object having initial velocity
u
is applied an acceleration of
a
for
t
time, its final velocity
v
is given by
v
=
u
+
a
t
and distance covered
S
is given by
S
=
u
t
+
1
2
a
t
2
.
We have
u
=
o
(as the object starts from rest),
t
=
5
sec., and acceleration
a
=
−
1.5
m
sec
2
.
Hence final velocity
v
=
−
1.5
×
5
=
−
7.5
m
sec
.
Distance covered
S
=
1
2
×
(
−
1.5
)
×
5
2
=
−
18.75
m
.
Minus sign indicates that acceleration is in reverse direction.
is applied an acceleration of
a
for
t
time, its final velocity
v
is given by
v
=
u
+
a
t
and distance covered
S
is given by
S
=
u
t
+
1
2
a
t
2
.
We have
u
=
o
(as the object starts from rest),
t
=
5
sec., and acceleration
a
=
−
1.5
m
sec
2
.
Hence final velocity
v
=
−
1.5
×
5
=
−
7.5
m
sec
.
Distance covered
S
=
1
2
×
(
−
1.5
)
×
If an object having initial velocity
u
is applied an acceleration of
a
for
t
time, its final velocity
v
is given by
v
=
u
+
a
t
and distance covered
S
is given by
S
=
u
t
+
1
2
a
t
2
.
We have
u
=
o
(as the object starts from rest),
t
=
5
sec., and acceleration
a
=
−
1.5
m
sec
2
.
Hence final velocity
v
=
−
1.5
×
5
=
−
7.5
m
sec
.
Distance covered
S
=
1
2
×
(
−
1.5
)
×
5
2
=
−
18.75
m
.
Minus sign indicates that acceleration is in reverse direction
5
2
=
−
18.75
m
.
Minus sign indicates that acceleration is in reverse direction.