Question

If sin theta = 1/3 what are the values of cos theta and tan theta?

Answer 1

`\cos\theta = \pm(2√(2))/(3)\\\tan\theta=\pm(√(2))/(4)`

Explanation:

sinθ = 1/3

`\cos\theta=\pm√(1-\cos^2\theta) = \pm\sqrt{1-(1)/(9)}=\pm\sqrt(8)/(9)=\pm(2√(2))/(3)`

`\tan\theta=(\sin\theta)/(\cos\theta)=\pm(1)/(2 √(2))=\pm(√(2))/(4)`