Question

If 5.32 mols N2 and 15.8 mols H2 react together, what mass NH3 can be

produced? Which is the limiting reactant?

Answer 1

2.87 gram

N2 is the limiting agent

Step-by-step explanation:

We will find out if there is sufficient N2 and h2 to produce NH3

a) For 2.36 grams of N2

Molar mass of N2 = 28.02

Number of moles of N2 in 2.36 grams = 2.36/28.02

Mass of NH3 = 17.034 g

Now NH3 produced form 2.36 grams of N2 =

2.36/28.02 * 2 * 17.034 = 2.87 g NH3

b) For 1.52 g of H2

NH3 produced = 1.52/2.016 * (2/3) * 17.034 = 8.56

N2 Is not enough to produce 2.87 g of NH3 and also H2 is not enough to make 8.56 g of NH3.

N2 is the limiting agent as it has smaller product mass