Answer:
The bracket is the binomial.
The definition is:
![\binom{n}{k} = (n!)/(k!\cdot (n-k)!)](https://img.qammunity.org/2022/formulas/mathematics/high-school/gjehyqur2g08l6k0i0qjxyv56tiwuwq39f.png)
Note that
![\binom{n}{k} = \binom{n}{n-k}](https://img.qammunity.org/2022/formulas/mathematics/high-school/ww8cevo246j889616l55pwtwn1v0s5orux.png)
The meaning is "if we have n elements, how many ways are there to choose k of them?" From this definition it should be obvious that
- if you're picking k, it's just as many ways as choosing the (n-k) that you're not picking.
The coefficient can be found by realizing that to get x^9, we need to choose (from the full multiplication):
- 9 brackets to provide x
- 2 brackets to provide the number 3
There's
ways to do that, so the component for x^9 will be:
![\binom{11}{9} \cdot 3^2 \cdot x^9 = (11!)/(2!\cdot 9!) \cdot 3^2 \cdot x^9 = (10\cdot 11)/(2) \cdot 3^2 \cdot x^9 = 55 \cdot 9 \cdot x^9 = 495x^9](https://img.qammunity.org/2022/formulas/mathematics/high-school/gx26b87t30r3hvgd73ix5vnp56658x6h63.png)
So:
a = 2
Coefficient is 495