Question

- The pit of an aqueous solution of NaOH is 12.9. What is the molarity of the solution?

Answer 1

Answer: The molarity of solution is 0.08 M

Step-by-step explanation:

pH is the negative logarithm of hydrogen ion concentration. It tells abpout the acidity or basicity of a solution.

`pH=-log[H^+]`

also pH+pOH=14

given : pH of NaOH = 12.9

Thus pOH = (14-12.9) = 1.1

Thus
`[OH^-]=10^(-1.1)=0.08M`

As
`NaOH\rightarrow Na^++OH^-`

As 1 mole of
`OH^-` is produced by = 1 mole of NaOH

Thus 0.08 moles of
`OH^-` are produced by =
`(1)/(1)* 0.08=0.08` moles of NaOH

The molarity of solution is 0.08 M