160k views
1 vote
Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.

1 Answer

7 votes

Answer:

The total amount of energy required is 25,515.2 J.

Step-by-step explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

  • experience a change in its temperature, which involves sensible heat,
  • undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

  • Q: amount of heat
  • m: mass
  • L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

  • Q: amount of sensible heat
  • m: body mass
  • c: specific heat of the substance
  • ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is 4.184
(J)/(g*C):

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184
(J)/(g*C))* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36
(J)/(g):

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36
(J)/(g)) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is 2.02
(J)/(g*C) :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02
(J)/(g*C))*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

The total amount of energy required is 25,515.2 J.

User Robinkc
by
8.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.