A spinner has the numbers 11-20 on it. What is the probability that it will land on a multiple of 3?

Question

asked Jun 17, 2022 39.7k views

1 Answer

NSA · Answer 1 · 2022-06-23T23:18:00+0000

Answer:

P(A) = (3)/(10)

Explanation:

Given

$S = \{11,12,13,14,15,16,17,18,19,20\}$

Required

The probability of having a multiple of 3

Let the event of having a multiple of 3 be represented as: A

So:

$A = \{12,15,18\}$

n(A) = 3

So, the probability is:

P(A) = (n(A))/(n(S))

Where

n(S) = 10 i.e. the sample size

So:

P(A) = (n(A))/(n(S))

P(A) = (3)/(10)