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Can someone help me please

Can someone help me please-example-1
User Bjmc
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1 Answer

5 votes

Answer:

1: x = 6

2: There is no solution. Sorry. (because the ending equation will be 0 = 7)

3: I can't see the other part of the equation, I need to see what the fraction is in order to solve it. If you can retake the picture, I can edit my response :)

Explanation:

#1: 3(x-1) is pretty much just 3x-3. Simple.

Now, your equation becomes 3x-3 = 2x+9.

Arrange them so that the like terms are together.

Since you will be taking the 2x from 2x+9 over to the other side, it becomes 3x-2x-3 = 9.

Now, bring the 3 over to the side with the 9.

x = 6.

#2: Same as before, -2(x+1) is (-2x) - 2.

So, -2x-2 = -2x+5.

As I said before, you need to group the like terms together.

-2x and -2x go together, and -2 and 5 go together.

-2x+2x=5+2

0=7.

There is no solution.

#3: Like the other two, 4(x-1) is 4x-4. As for the other part, I cannot see the fraction before (x-8).

User Elliott Hughes
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