179,303 views
2 votes
2 votes
Please answer now ! 90 points

Please answer now ! 90 points-example-1
User Dorkus Prime
by
3.5k points

2 Answers

3 votes
3 votes

Answer: a)7, B)8

Explanation:

Problem a) If Kai wants to buy just one poster that costs 2 dollars, he has 25-2=23 dollars left. If each book is 3 dollars, then he can buy 23/3 books. The inequality that results is that if b=#ofbooks, then b< or = (25-2)/3, because you cant buy a book for 2 and a half dollars, hence the less than. 23/3 is 7 r2. We get that b< or = to 7 2/3. However, he can't buy 2/3 of a book, so 7. The final inequality we get is that 2+3b<=25

Problem 2) She spends 50 initially, so 200-50=150 dollars left. Thus the number of lessons, or n, cover the rest of the money. Using the same thory as above, the final inequality is 50+25n<=200. n=8.

User Khurrum
by
3.7k points
2 votes
2 votes

Explanation:

  • 2+3b
    \leq25

b=books

3b
\leq23


b\leq 23/3


b\leq 7.67

  • 50+25L
    \leq200

L=lesson

25L
\leq150

L
\leq6

Hope that helps :)

User Shahidh
by
2.8k points