Question

A block of iron has dimensions of 1 cm x 2 cm x 5 cm and has a

mass of 799
What is its density? (V=lxwxh)

Answer 1

79.9 units

Explanation:

Hi there,

Before solving this problem, it is important to know the formula:

D =
`(m)/(v)`.

D = density

m = mass

v = volume

Since we are given the mass and volume, we can simply enter these values into the formula to find the density of the block.

D =
`(799)/(10)`

D = 79.9

Therefore, the density of the block of iron is 79.9 units. I wrote units since you did not specify the unit for the mass. Hope this answer and explanation helps.

Cheers.